How to prove (ab)^t=b^ta^t?

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Answers ( 17 )

  1. Prudence

    Prove that $$-(ab^{-1}) = (-a)b^{-1} = a(-b^{-1}).$$ \begin (...) We have $$(AB - BA)^T = (AB)^T - (BA)^T = B^TA^T - A^TB^T = -BA - A(-B) = AB - BA.$$ \end{answer} \end
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  2. Bethany

    (definition of composition TS) = [T(b 1) T(b 2) (...) T(b k)] (B is matrix for S: B (...) We have seen the associativity (AB)C = A(BC) for the matrix multiplication
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  3. Cindy

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  4. Määman

    Verification of (AB)^t=A^tB^t for Matrices :

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  5. Paély

    Consider the matrix $B = \left(\matrix{1 & 1 \\ 0 & 2}\right)$. Find its eigenvalues. Prove, without any computation, that this matrix has an eigenbasis.
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  8. Wyatt

    How to proof (AB)^T = (B^T)(A^T) :

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  10. Erin

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  11. Porlur

    Example of Skew-Symmetric Matrix :

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  12. Bloodsword George

    ThinkTibits! Home; Java. Apache POI; iText; (...) (AB)^T=B^TA^T $ 2) Solve: (...) $, prove that $ \overrightarrow{r}=(\overrightarrow{r}
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  14. Spider Sam

    Introduction to the transpose of a matrix (ABCD)^T =D^TC^TB^TA^T :

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  15. Karen

    How to prove that adj(A.B) = adj(B).adj(A)? :

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